My laptop has 16GiB: Difference between revisions
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Created page with "My MacBook has 17,179,869,184 bytes of RAM, and not 16,000,000,000. Recall that 17,179,869,184 = 16GiB = 16 x 2^30, which is the correct measurement under IEC 60027-2. 16GB..." |
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My MacBook has 17,179,869,184 bytes of RAM, and not 16,000,000,000. Recall that 17,179,869,184 = 16GiB = 16 x 2 | My MacBook has 17,179,869,184 bytes of RAM, and not 16,000,000,000. Recall that 17,179,869,184 = 16GiB = 16 x 2<sup>30</sup>, which is the correct measurement under IEC 60027-2. 16GB would be 16,000,000,000 = 16 x 10<sup>9</sup>. | ||
The differences between 1 KiB and 1 KB is not significant, but when you get up to the Gibibytes, the differences are indeed significant! | The differences between 1 KiB and 1 KB is not significant, but when you get up to the Gibibytes, the differences are indeed significant! | ||
For more information, see https://physics.nist.gov/cuu/Units/binary.html | For more information, see https://physics.nist.gov/cuu/Units/binary.html | ||
Revision as of 07:41, 27 April 2018
My MacBook has 17,179,869,184 bytes of RAM, and not 16,000,000,000. Recall that 17,179,869,184 = 16GiB = 16 x 230, which is the correct measurement under IEC 60027-2. 16GB would be 16,000,000,000 = 16 x 109.
The differences between 1 KiB and 1 KB is not significant, but when you get up to the Gibibytes, the differences are indeed significant!
For more information, see https://physics.nist.gov/cuu/Units/binary.html
